Question

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он
QH
QH
-NO2
Sam
+ dil. HNO3
6
25°C
Phenol
0-Nitrophenol
(40%)
ΝΟ.
p-Nitroph
(14%​

Answer 1

Answer:

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Answer 2

Explanation:

calculate molality,molarity and mole fraction of KI if the density of 20% (mass/mass) aqueous KI is 1.202 g/ml? M of KI = 145 g/mol and H2O =18g /mol.

Giv20% means 100g of solution has 20g. mass of solvent = 100-20 = 80, Mass of soln= 100, d = 1.202 g mL volume of solution= 83.19 mL, moles of KI = 20/145=.1379 moles

Molarity= 1000X.1379/83.19= 1.65M

molality= 1000x.1379/80= 1.723 m

moles of KI=.1379 and water = 80/18=4.444 total no. of moles = 4.5819

mole fraction of KI = .1379/ 4.5819= .0300