Math, asked by amitlsharma2004, 5 hours ago

y=sin^-1(3sinx-4sin^3x) Find dy/dx w.r.t.x​

Answers

Answered by senboni123456
2

Step-by-step explanation:

We have,

y =  \sin^{ - 1}  \{3 \sin(x)  - 4 \sin^{3} (x)  \}

 \implies \: y =  \sin^{ - 1}  \{3 \sin(x)  - 4 \sin^{3} (x)  \} \\

 \implies \: y =  \sin^{ - 1}  \{ \sin(3x)   \} \\

 \implies \: y = 3x    \\

 \implies \:  \frac{dy}{dx}  = 3    \\

Answered by khairnarsiddhi053
0

y=3x

\begin{gathered} \implies \: \frac{dy}{dx} = 3 \\\end{gathered}

dx

dy

=3

dx

dy

=3

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