Math, asked by umaselvaraj001, 26 days ago

y=sin^-1(√x+1/√x-1) + sec ^-1 ( √x-1/√x+1)find dy/dx

Answers

Answered by saikinneragsailokesh
0

y = sec-1((x+1)/(x-1)) + sin-1((x-1)/(x+1))

= cos-1((x-1)/(x+1)) + sin-1((x-1)/(x+1))

= π/2

dy/dx = 0

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