Question

y=sin^-1[x ÷ √(1+x²)]​

Answer 1

Step-by-step explanation:

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Answer 2

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y = sin^-1[x /sqrt( 1+ x^2)]

let x = tan@

y = sin^-1 tan@/sec@

y = @

y = tan^-1x

diffrenciating w.r. to x we get

dy/dx = 1/1 + x^2)

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