Math, asked by shilpakumari93, 9 months ago

y = sin^(-1)(x/√1+x²) + cos^(-1)(1/√1+x²) , the value of dy/dx is:.

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Answered by saindulakavath

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y = sin^(-1)(x/√1+x²) + cos^(-1)(1/√1+x²) , the value of dy/dx is:.​

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y = sin^(-1)(x/√1+x²) + cos^(-1)(1/√1+x²) , the value of dy/dx is:.