Question

y= sin^2 x+sin x+1
Find interval (or range) of y .

Answer 1

Answer:

[-1,3]

Step-by-step explanation:

sin x : [-1,1]

sin²x: [0,1]

(sin²x + sinx) : [0,1]+[-1,1] = [-1,2]

(sin²x + sinx+1): [-1,2]+[1,1] = [-1,3]

(sin²x + sinx+1): [-1,3]