y=sin(5-3x) nth diff.
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y = sin(5-3x)
f'(x)= cos(5-3x)(0-3)
f''(x) = -3cos(5-3x)
f'''(x) = -9 sin(5-3x)
f'''(x) = -9 * f(x)
f'(x)= cos(5-3x)(0-3)
f''(x) = -3cos(5-3x)
f'''(x) = -9 sin(5-3x)
f'''(x) = -9 * f(x)
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aage n*(-3) kr de bs ho jayega
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