Question

y= sin^98x . cos^39x then find Dy/dx​

Answer 1

Answer:

Given

cos(x+y)=ysinx

Differentiating both sides with respect to x, we get

−sin(x+y){1+dxdy}=ycosx+sinxdxdy

−sin(x+y)−sin(x+y)dxdy=ycosx+sinxdxdy

⇒−sin(x+y)dxdy−sinxdxdy=ycosx+sin(x+y)

⇒{−sin(x+y)−sinx}dxdy=ycosx+sin(x+y)

⇒dxdy=sin(x+y)−sinxycosx+sin(x+y).

Step-by-step explanation:

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