Math, asked by sriganesh55500, 10 days ago

y = sin(sin(sin(cosx))) Find y'

Answers

Answered by sandeepsahaniofficia

0

Step-by-step explanation:

y'=cos(sin(sin(cosx))).cos(cos(sin(cosx))).cos(cos(cos(cosx))).cos(cos(cos(-sinx)))

y'=cos(sin(sin(cosx))).cos(cos(sin(cosx))).cos(cos(cos(cosx))).cos(cos(cos(sinx)))

y'=cos(sin(sin(cosx))).cos(cos(sin(cosx))).cos(cos(cos(cosx))).cos(cos(sin(cosx)))

y'=cos(sin(sin(cosx))).cos²(cos(sin(cosx))).cos(cos(cos(cosx)))

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