Question

Y=sin (€t-kx) then value of dy/dx is

Answer 1

please check on Google

Answer 2

$\large\mathfrak \red{Given:-}$

$\tt{y = \sin(wt - kx) }$

$\large\mathfrak \red{Solution:-}$

$\: \: \: \tt{ let \: (wt - kx) \: be \: x.}$

$\tt{We \: know \: that, }$

$\tt {\frac{dy}{dx} = \sin x.}$

$\: \: \: \: \: \tt{= \cos x.}$

$\tt \blue{A/Q,}$

$\: \: \: \: \: \: \tt {\frac{dy}{dx} = \cos(wt - kx) (0 - k)}$

$\: \: \: \: \: \: \tt {\frac{dy}{dx} = - k\cos(wt - kx)}$