y=sin x/x, find dy/dx
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1
Answer:
y=sinx
x
On differentiating both sides w.r.t x, we get
dx
dy
=
dx
d
(sinx
x
)
dx
dy
=cos(x
x
)
dx
d
(x
x
)
dx
dy
=cos(x
x
)(x
x
)
dx
d
(xlnx)
dx
dy
=(x
x
)cos(x
x
)(lnx×1+x×
x
)
dx
dy
=(x
x
)cos(x
x
)(lnx+1)
Hence, this is the answer.
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