Question

y=sin²x find dy/DX at x=30 degree

pls tell fast​

Answer 1

Answer:

$y=sin^2x\\\frac{dy}{dx} =2sinxcosx\\At x=30 , \frac{dy}{dx}=2sin30cos30=2.\frac{1}{2}.\frac{\sqrt{3} }{2} =\frac{\sqrt{3}}{2}$

Step-by-step explanation: