Question

y=sin2x+sin4x+sin6x

dy/dx=?

Answer 1

we know y=sin2x+sin4x+sin6x

so dy/dx= d/dx(sin2x+sin4x+sin6x)

d/dx of sintheta is cos theta and 2x is 2

that implies the answer 2cos2x+4cos4x+6cis6x