Question

y= sin²x then dy/dx is ?

1. sinx
2. 2sinx
3. 2sinxcosx
4.cosx​

Answer 1

Answer:

You would use the chain rule to solve this. To do that, you'll have to determine what the "outer" function is and what the "inner" function composed in the outer function is.

In this case,

sin(x)

is the inner function that is composed as part of the

sin2(x).

So, mathematically, the chain rule is:

F'(x)=f'(g(x))(g'(x)) where g(x) is inner function and f(g(x)) is outer one.

1) The derivative of the outer function(with the inside function left alone) is:

f'((sin(x))^2) = 2sin(x)

2) The derivative of the inner function:

g'(sin(x)) =cos(x)

Combining the two steps through multiplication to get the derivative as :

2sin(x)cos(x).

Have a nice day!!

Answer 2

Answer:

2

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