Question

y=sinx-cosx then its dy/dx is​

Answer 1

Answer:

Step-by-step explanation:

y=sinx-cosx

dy/dx=d(sinx-cosx)/dx

=d((sinx)-d(cosx))/dx      [d(sinx)/dx=cosx and d(cosx)/dx=-sinx]

=cosx-(-sinx)

ANSWER="cosx+sinx"