Question

y = Sinx .tanx
find dy/dx

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Answer 1

Answer:

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y= sinx.tanx

Step by step explanation

derivative of sinx is cosx

derivative of tanx is sec²x

Answer 2

$y = sinx.tanx \\ \\ \frac{dy}{dx} = sinx \frac{d}{dx} tanx + tanx \frac{d}{dx} sinx \\ \\ \frac{dy}{dx} = sinx {sec}^{2} x + tanxcosx \\ \\ \frac{dy}{dx} = tanxsecx + sinx$