Question

y=sinx+tanx. Find dy/dx at x=45°.​

Answer 1

$y = sinx + tanx \\ \\ \frac{dy}{dx} = cosx + {sec}^{2} x \\ \\ \frac{dy}{dx} \: \: \: \: at \: \: x = 45 \degree \\ \\ \frac{dy}{dx} = cos45 \degree + {sec}^{2} 45 \degree \\ = \frac{1}{ \sqrt{2} } + 2$