Question

y=sinx/x^2 find dy/dx​

Answer 1

Answer:

         -2x⁻³cos x

Step-by-step explanation:

y = sin x / x²                

y = sin x × x⁻²

dy / dx = d sin x × x⁻² / dx

= d sin x × x⁻² / dx                       { d/dx sin x = cos x}       { d/dx  xⁿ = nxⁿ⁻¹}

= cos x × -2x⁻²⁻¹

= cos x × -2x⁻³

= -2x⁻³cos x

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