Question

Y=sinx/x+cosx , then dy/dx=?

Answer 1

Answer:

dy/dx=(du/dx)+(dv/dx)

=((xcosx-sinx)/(x) 2)+-sinx

Step-by-step explanation:

y=sin x/x +cos x

we get,

u= sinx/x

diff. w. r. t. x

du/dx= d/dx (sinx /x)

=(xcosx-sinx)/(x) 2

v=cosx

diff. w. r. t. x

dv/dx=d/dx(cosx)

=-sinx

dy/dx=(du/dx)+(dv/dx)

=((xcosx-sinx)/(x) 2)+-sinx