Question

(y square + 5y) (y square + 5y -2) -24 = 0​

Answer 1

Use the laplace transform to solve the following intial value problem:

y"-4y'+5y=0 y(0)=0, y'(0)=1

Using Y for the Laplace transform of y(t), i.e. Y=L{y(t)},

find the equation you get by taking the Laplace transform of the differential equation

_________________________________=0

Now solve for Y(s)=_______________________________

By completing the square in the denominator and inverting the transform, find

y(t)=___________________________________

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