Question

Y
Sum of digit of a two digit number is 11.
If the digits are interchanged the number so got
is 27 more than it. Find the numbers​

Answer 1

Answer:

Original number= 110- 9x= 47

New number= 9x+ 11= 74

Step-by-step explanation:

Let the digit at one's place be x

∴ The digit at ten's place= 11-x

The original number= 10( 11-x )+ x

                                 = 110-10x+x

                                 = 110-9x

When digits are interchanged,

New number= 10(x)+11-x

                     = 10x +11-x

                     = 9x+11

∴ New number= Original number+ 27

  9x+11 = 110-9x +27

  18x=  137-11

  18x= 126

∴ x= 7

Original number= 110- 9x= 47

New number= 9x+ 11= 74