Question

y=tan^-1[(1+tan x)÷(1-tan x)], find dy/dx​

Answer 1

Dear friends

The answer is given below

Y=tan^-1(1+tanx/1-tanx)

dy/dx=tan^-1(1+tanx/1-tanx)

Tan^-1*tan(π/4+x)

Y=π÷4+x

Where x belongs to [-π/4,π/4]

Dy/dx=0+1=1