Question

y = (tan 2x)/(cos sec(3x))

Answer 1

Answer:

=3sec23x−2sec22x−sec2x

Step-by-step explanation:

We know

tan3x=tan(x+2x)

=1−tanx.tan2xtanx+tan2x

By cross multiplication, we get

tan3x−tanxtan2xtan3x=tanx+tan2x

tanxtan2xtan3x=tan3x−tan2x−tanx=y

dxdy=dxd(tan3x−tan2x−tanx)

=3sec23x−2sec22x−sec2x