Question

Y = ( tanX )^SecX
Snap. - harshitsolankix

Answer 1

$\Large \colorbox{red}{ \sf\color{white}{Aиswεr : }}$

$y = ( \tan(x) {)}^{ \sec(x) }$

Answer 2

$Given: y=tanx+secx</p><p>Prove that: dx2d2y=(1−sinx)2cosx</p><p>y=cosxsinx+cosx1</p><p>=cosx1+sinx</p><p>differentiate with respect to x</p><p>dxdy=dxd(cosx1+sinx)</p><p>dxdy=cos2xcosxdxd(1+sinx)−(1+sinx)dxdcosx</p><p>=cos2xcos2x+sinx+sin2x=cos2x1+sinx=1−sin2x1+sinx</p><p>=(1+sinx)(1−sinx)1+sinx=1</p><p></p><p>$