Question

y= tanx•sinx then dy/dx​

Answer 1

$y = sinx.tanx \\ \\ \frac{dy}{dx} = sinx \frac{d}{dx} tanx + tanx \frac{d}{dx} sinx \\ \\ \frac{dy}{dx} = sinx {sec}^{2} x + tanxcosx \\ \\ \frac{dy}{dx} = tanxsecx + sinx$