Question

Y=tanx^tanx^tanx difranceation

Answer 1

Answer:

Step-by-step explanation:

kunki tanx repeat ho raha hai isliye

y=tanx^y

taking log both side

logy=logtanx^Y

logy=y logtanx

differentiation karne pr x ki respect me

1/y dy/dx = y . 1/tanx .  sec²x + logtanx . dy/dx

dy/dx(1/y-logtanx)=ysec²x/tanx

dy/dx(1-y logtanx/y)=ysec²x/tanx

dy/dx=y²sec²x/tanx(1-ylogtanx)

Answer 2

Answer:

Step-by-step explanation:

y=tanx^y

taking log both side

logy=logtanx^Y

logy=y logtanx

differentiation karne pr x ki respect me

1/y dy/dx = y . 1/tanx .  sec²x + logtanx . dy/dx

dy/dx(1/y-logtanx)=ysec²x/tanx

dy/dx(1-y logtanx/y)=ysec²x/tanx

dy/dx=y²sec²x/tanx(1-ylogtanx)