Question

y
$y = \sqrt{1 - cos2x \div \sqrt{1 + cos2x} }$
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Answer 1

Answer:

y=secx-cosx

Step-by-step explanation:

first you must remember :-cos2x=2cosx^2-1

$y = \sqrt{1 - cos2x \div \sqrt{1 + cos2x} }$