Question

y............
u
y
u............

Answer 1

Step By Step Explanation:-

Given:-

Triangle ABC
BD=BC
/_B=60°
/_A=70°

To prove:-
(i)AD>CD
(ii)AD>AC

Proof:-

BD=BC(given)
So, /_BCD=/_BDC=x° (angles opposite to equal sides are equal)

/_CBA=60°
So, /_CBD=180-60
=120°
In triangle BCD:-
/_CBD+/_BDC+/_BCD=180°(Angle sum property)
120°+2x=180°
x=30°
So,/_BDC=/_BCD=30°

/_ACD=/_ACB+/_BCD
=50+30=80°

(i)/_ACD>/_CAD
So,side AD>CD

(ii)/_ACD>CDA
So, side AD>AC

Hence proved

I hope it helps you