Question

y=under root of 1-cosx/1+cosx find dy/dx​

Answer 1

Answer:

dy/dx=1/2sec squareX/2.

y=under root 1-cosx/1+cosx

y=under root 2sin square X/2÷2cos square X/2

y=tanX/2.

dy/dx=sec square X/2 × dX/2

=1/2 sec square X/2.