Question

y= under root tan x+y
$y = \sqrt{tan \: x + y}$
if y= under root tan X+Y then prove that (2y-1)dy/ dx = sec 2
square x
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Answer 1

Step-by-step explanation:

y= under root tan x+y

$y = \sqrt{tan \: x + y}$

if y= under root tan X+Y then prove that (2y-1)dy/ dx = sec 2

square x

Answer 2

see the answer in pic

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