Question

y= underroot over 1+tanx/1-tanx find dy/dx

Answer 1

Answer:

I don't know

Step-by-step explanation:

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Answer 2

Answer:

dy/dx =sec²x/(1-tanx)²

Step-by-step explanation:

y=√{(1+tanx)/(1-tanx)}

y²=(1+tanx)/(1-tanx)

using the division rule

2ydy/dx ={(1-tanx)d/dx (1+tanx)-(1+tanx)d/dx (1-tanx)}/(1-tanx)²

:-d/dx tanx =sec²x

2ydy/dx {(1-tanx)sec²x-(1+tanx)(-sec²x)}/(1-tanx)²

dy/dx =1/2 {sec²x-sec²xtanx+sec²x+sec²x.tanx}/(1-tanx)²

dy/dx =1/2(2sec²x)/(1-tanx)²

dy/dx =sec²x/(1-tanx)² Ans

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