Question

Y varies directly as the sqaure root of x. when x= 16, y =24. find the constant of variation and the equation of variation

Answer 1

$y \: \infty \: \sqrt{x} \\ y = k \sqrt{x} \: \: < < k = constant > > \\ \: then \\ k = \frac{y}{ \sqrt{x} } \\ = \frac{24}{ \sqrt{16} } \\ = \frac{24}{ \sqrt{ {4}^{2} } } \\ = \ \frac{24}{4} = 6$