Question

y varies directly as x^2 and inversely as z. If y = 12 when x = 2 and z = 7, find y when x = 3 and z = 9.

Answer 1

Answer:

Y=27

Step-by-step explanation:

Y is directly proportional to x^2 and inversely to z

So, Y= k.x^2/z  ( k is a constant)

If y =12, x=2, and z=7

Then,

12=k.2^2/9

k=27

Now, x=3, k=27, z=9

Y=kx^2/z

Y=27.3^2/9

Y=27

I hope this helps. Please mark as the brainliest