y varies inversely with x. if y = 30 when x = 12 , find y when x = 15
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Step-by-step explanation:
yx=k
k=30×12=360
in second case
y15=360
So y=360/15
y=24
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Given that, y ∝ (1/x) ∴ y = k x (1/x) where, k is the constant of variation. ∴ y × x = k …(i) When x = 12, y = 30 ∴ Substituting, x = 12 and y = 30 in (i), we get y × x = k ∴ 30 × 12 = k ∴ k = 360 Substituting, k = 360 in (i), we get y × x = k ∴ y × x = 360 ….(ii) i. When x = 15,y = ? ∴ Substituting x = 15 in (ii), we get y × x = 360 ∴ y × 15 = 360 y = 360/15 y = 24 ii. When y = 18, x = ? ∴ Substituting y = 18 in (ii), we get y × x = 360 ∴ 18 × x = 360 x = 360/18 x = 20Read more on Sarthaks.com - https://www.sarthaks.com/855158/y-varies-inversely-with-x-if-y-30-when-x-12-find-i-y-when-x-15-ii-x-when-y-18
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