Question

y varies jointly as x and the square root of z . If y = 6 when x = 3 and z = 9, find y when x = 4 and z = 36.

Answer 1

Answer:

y = 10

Step-by-step explanation:

$y =x+\sqrt{z} \\If,\\x=4 and z=36\\y= 4 +\sqrt{36} \\y= 4 +6\\y=10$

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Answer 2

Step-by-step explanation:

y=kx√z

6=k(3) √(9)

6=k(3)(3)

6=9k both divide to 9

so it's k=0.6666

or 6/9

y=kxz

y=(6/9)(4)(36)

so the answer is: y=96

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