Question

Y variesinversely with x .If y=30 when x=12 find y when x=15

Answer 1

$\huge\bold\color {green}{Hello \: Friend \: !!}$


$\red {\bold {Here \: is \: your \: answer}}$


$\underline\bold {Answer : y = 24 }$


$\purple {\underline\bold {↪ Given :}}$


$\bold {x_1 = 12}$


$\bold {y_1 = 30}$


$\bold{x_2 = 15}$


$\bold {↪ Y \: varies \: inversely \: with \: X}$


$\orange{\underline\bold {↪ To \: Find : Find \: the \: value \: of \: Y_2}}$


$\red {\underline\bold {↪ Solution :}}$


$\bold {x_1 × y_1 = x_2 × y_2}$


$\bold {12 × 30 = 15 × y_2}$


$\bold {12 × 2 = y_2}$


$\bold {y_2 = 24}$



$\mathbb {\huge {\fcolorbox{yellow}{green}{Hope It Helps}}}$

Answer 2

$\huge\color{red}{Hello}$$\huge\color{red}{friends,}$

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$\huge\color{orange}\boxed{Answer}$

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$<b><i><u>So$ Simple

So , let's start

x 1 = 12 , y 1 = 30 , x 2 = 15

Y varies inversely with x ( GIVEN )

So ,

x 1 * y 1 = x 2 * y 2

12 * 30 = 15 * y 2

y 2 = 12 * 30 / 15

y 2 = 24






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$\huge\color{purple}\boxed{Answer = 24}$

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Hope you understand the topic .



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