Question

y=(x+1)^2(x^2+2). find dy/dx​

Answer 1

Step-by-step explanation:

By using product rule,

Let's take U=(x+1)² and V=(x²+2)

Then, dy/dx=U.dV/dx+V.dU/dx

=> dy/dx=(x+1)².d/dx(x²+2)+(x²+2).d/dx(x+1)²

=(x+1)².2x+(x²+2).2(x+1).d/dx(x+1)

=2x²+2x+4x²+2x³+4x+x²+2

=2x³+7x²+6x+2