Question

Y=(x+1)/(x-2) solve the differentiation.

Answer 1

Answer:

y'=[(x-2)-(x+1)]/(x-2)^2

y'=(-3)/(x-2)^2

hope it helps you dear☺️☺️☺️

Answer 2

$\large{ \underline{ \underline{ \bigstar{ \: \: \: \: \: { \pmb{ \sf{Solution \: : }}}}}}}$

$\dashrightarrow \tt \: y = \frac{(x + 1)}{(x - 2)}$

$\dashrightarrow \tt \frac{dy}{dx} = \frac{1}{ {(x - 2)}^{2} } \bigg((x - 2)\frac{d}{dx} (x + 1) - (x + 1) \frac{d}{dx} (x - 2) \bigg)$

$\dashrightarrow \tt \frac{dy}{dx} = \frac{1}{ {(x - 2)}^{2} } \bigg((x - 2) - (x + 1) \bigg)$

$\dashrightarrow \frak \blue{ \frac{dy}{dx} = - \frac{3}{ {(x - 2)}^{2} } }$

$\large{ \underline{ \underline{ \bigstar{ \: \: \: \: \: { \pmb{ \sf{Formal \: \: Used \: : }}}}}}}$

$\longrightarrow \frac{d}{dx} \big(f(x) /g(x) \big) = \frac{g(x) f'(x) -f(x) g'(x) }{\{g(x) \}²}$

$\\ \\ \frak \colorbox{aqua}{BriefReflexion}$