Question

y = √x +1/√x, then dy/dx at x=1 is​

Answer 1

Step-by-step explanation:

We have,

$y = \sqrt{x} + \frac{1}{ \sqrt{x} }$

Differentiating both sides w.r.t x, we have,

$\frac{dy}{dx} = \frac{1}{2 \sqrt{x} } - \frac{1}{2} {x}^{ - \frac{3}{2} }$

Now, at x=1,

$\frac{dy}{dx} = \frac{1}{2} - \frac{1}{2} (1) ^{ - \frac{3}{2} }$

$= 0$