Question

y=√x-1/√x to find dy/dx

Answer 1

y = √(x -1)/√x

take square both sides,

y² = (x -1)/(x )

y² = x/x - 1/x

y² = 1 - 1/x

now differentiate wrt x

2y.dy/dx = 0 +1/x²

2ydy/dx = 1/x²

dy/dx = 1/2yx²

put y = √(x -1)/√x

dy/dx = √x/2√(x-1)x²

Answer 2

Hi friend!!!!

Given, y=√x-1/√x

squaring on both sides ,we get

y²=(x-1)/x

y²=1-1/x

differentiating with respect to x ,we get

2y dy/dx= 1/x²

dy/dx =1/2yx²
=1/2x²*(√x-1/√x)

I hope this will help u ;)