Question

y= x+2/x^2+1
find dy/DX
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Answer 1

Step-by-step explanation:

$y = x + \frac{2}{ {x}^{2} } + 1 \\ \frac{dy}{dx} = 1 + 2( - 2)( {x}^{ - 2 - 1} ) + 0 \\ \frac{dy}{dx} = 1 - 4( {x}^{ - 3} )$

Answer 2

Answer:

y = x+ 2/x^2 +1

differentiate wrt x

dy = dx -4/x^3 dx +0

dy/dx = 1-4/x^3

= (x^3-4)/x^3