Question

y(x^2*y+e^x)dx-e^x*dy=0​

Answer 1

answer

l y ( 2xy + e^x ) dx - e^xdy = 0 y ( 2xy + e^x ) dx = e^xdy y ( e^xdx - e^xdy ) + 2xy^2dx = 0 Divide by y^2 e^x/y dx - e^x/y^2 dy + 2xdx = 0 ye^xdx - e^xdy/y^2 ...  More

• hence Divide by y^2 e^x/y dx - e^x/y^2 dy + 2xdx = 0 ye^xdx - e^xdy/y^2