Y = (x^3 - 2X - 1)^5, find Dy/dx?
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Answer:
5 (x^3 - 2X - 1)^4 ( 3x^2 -2)
Step-by-step explanation:
Given: Y = (x^3 - 2X - 1)^5
To find: Dy/dx
Solution:
Dy/dx = d (x^3 - 2X - 1)^5 /dx
= 5 (x^3 - 2X - 1)^4 ( 3x^2 -2) .............(using chain rule)
=5 (x^3 - 2X - 1)^4 ( 3x^2 -2) is the answer
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