Question

y=x^3-2x+7 at (1,6)​

Answer 1

Answer:

y^1=1

Step-by-step explanation:

$y = {x}^{3} - 2x + 7 \\ \\ \frac{dy}{dx} = 3 {x}^{2} - 2 \\ \\ \frac{dy}{dx} = 3 {(1)}^{2} - 2 = 1$

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