Math, asked by nonie17, 12 hours ago

(y-x)³; where x=1, and y=3

Answers

Answered by divyapakhare468
2

Answer:

To find : (y-x)³

Given : x = 1, and y = 3

substituting value of x and y in equation

(y-x)³ = (3 -1 )^{3}

         = 2^{3}

         = 2 x 2 x2

         = 8

Therefore , the value of  (y-x)³ is 8.

Answered by Choudharipawan123456
1

According to the given question we have to find the value of

(y-x)^3

Given:- x=1, and y=3

Now, substitute the given value of x and y as 1 and 3,

So, we will get

=>(y-x)^3=(3-1)^3

                   =(2)^3

Here, the power of the number 2 is 3, so the number is multiplied by three-time,

=>(y-x)^3=2\times2 \times 2

=>(y-x)^3=8

Hence, the value of (y-x)^3 is 8.

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