Question

y=x+5;3x+5y=57.find xandy by substitution method

Answer 1

y=x+5,....................(1)
3x+5y=57................(2)

substitute y value in equation(2)
3x+5(x+5)=57
3x+5x+25=57
8x=57-25
8x=32
x=32/8
x=4
substitute x value in equation (1)
y=4+5
y=9

please pick it as best

Answer 2

y=x+5 , 3x+5y=57
3x+5(x+5)=57
3x+5x+25=57
8x=57-25
8x=32
x=32/8
x=4
given, y=x+5
i.e y=4+5
     y=9
Therefore, x=4 and y=9