y=(x-7)/(x-2)(x-3) then how dy/dx= 1-y(2x-5)/(x-2)(x-3).please explain this step- ex-18 ,from app.of deriv. This is the question--
Find the equation of the tangent to the curve y= (x-7)/(x-2)(x-3) at the point where it cuts the x-axis.
Answers
Answered by
1
refer to this given link
https://img-nm.mnimgs.com/img/study_content/content_ck_images/images/m23.png
Similar questions