Question

y = x cube + 2 X square + 7 x + 3 then DY by DX equals to​

Answer 1

Given:

y=x³+2x²+7x+3

Differentiate y,i.e.,dy/dx

Using the Formula,

$\sf{x {n}^{x - 1} }$

Now,

$\sf{ \frac{dy}{dx} = \frac{d(x {}^{3} + 2x {}^{2} + 7x + 3) }{dx} }$

We know that,

Differentiation of a constant is zero

Here,

$\implies \: \sf{\frac{dy}{dx} = 3x {}^{2} + 4x + 7 }$

Thus,dy/dx=3x²+4x+7