y=x.logx then dy/dx will be
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Answered by
1
Differentiating both sides
We get
dy/dx = x ( 1/x ) + logx (1 )
( Using multiply one formula )
We get
1+ logx
Mark as brainliest if u got that
We get
dy/dx = x ( 1/x ) + logx (1 )
( Using multiply one formula )
We get
1+ logx
Mark as brainliest if u got that
Answered by
1
Hii friend,
Here is your answer_______________
Here the condition has two variables.
Them by using chain rule,
(UV)’ => UV' +u'v
dy/dx. => x.1/x + 1.log x
{log x => 1/x}
dy/DX => 1+ log x.
Hope this helps you a little!!!
Here is your answer_______________
Here the condition has two variables.
Them by using chain rule,
(UV)’ => UV' +u'v
dy/dx. => x.1/x + 1.log x
{log x => 1/x}
dy/DX => 1+ log x.
Hope this helps you a little!!!
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