Question

y=(x+sec x)(x-tan x) differentiate wrt x.​

Answer 1

$y = (x + secx)(x - tanx) \\ \frac{dy}{dx} = (x + secx)(1 - {sec}^{2} x) + (x - tanx)(1 + secxtanx) \\ \frac{dy}{dx} = x - x {sec}^{2} x + secx - {sec}^{3} x + x + xsecxtanx - tanx - secx {tan}^{2} x \\ \frac{dy}{dx} = 2x + secx - {sec}^{3} x - x {sec}^{2} x - tanx + xsecxtanx - secx {tan}^{2} x$